State and prove De Morgan's theorem for Boolean Algebra. Simplify a given Boolean expression.
Model Answer
Boolean Algebra is an algebraic structure dealing with binary variables (0 and 1) and logical operations (AND, OR, NOT). It was developed by George Boole and is fundamental to digital circuit design.
1De Morgan's Theorems
2Statement of De Morgan's Theorems
The complement of the OR of two variables equals the AND of their complements: (A + B)' = A' · B'
The complement of the AND of two variables equals the OR of their complements: (A · B)' = A' + B'
3Proof of Theorem 1: (A + B)' = A'B'
4Example Simplification
5Key Boolean Laws (for simplification)
A + 0 = A and A · 1 = A
A + 1 = 1 and A · 0 = 0
A + A' = 1 and A · A' = 0
A + A = A and A · A = A
(A')' = A
A + AB = A and A(A+B) = A
A(B+C) = AB + AC and A + BC = (A+B)(A+C)
Key Formulas
(A + B)' = A' · B' (De Morgan's 1)
(A · B)' = A' + B' (De Morgan's 2)
A + A' = 1 (Complement)
A · A' = 0 (Complement)
A + AB = A (Absorption)
💡 Exam Tip
Always prove De Morgan's theorem with a truth table — it's the clearest method and gets full marks. For simplification questions, write each step on a new line and mention the law used (e.g., 'By Complement Law'). Examiners award marks per step.